A buffer solution is 0.374 M in and 0.275 M in . If ka for HClO is 3.5 x 10^-8 , what is the pH of this buffer solution?

Question

what is the ph

Answer 1

You can use the Henderson Hasselbalch equation:

pH = pKa + log [salt] / [acid]

pH = ?

pKa = -log Ka = -log 3.5x10-8 = 7.46

[salt] = 0.374 M (I'm guessing since you didn't put it in the original question)

[acid] = 0.275 M (I'm guessing since you didn't put it in the original question)

Solving for pH we have ...

pH = 7.46 + log (0.374 / 0.275) = 7.46 + 0.13

pH = 7.59