J.R. S. answered 12/04/22
Ph.D. University Professor with 10+ years Tutoring Experience
2H2S + 3O2 ==> 2SO2 + 2H2O .. balanced equation
100 g H2S x 1 mol H2S / 34 g = 2.94 mol H2S (÷2->1.47)
100 g O2 x 1 mol O2 / 32 g = 3.13 mols O2 (÷3->1.02)
Limiting reactant = O2 b/c 1.02 is less than 1.47
Grams of SO2 formed = 3.13 mol O2 x 2 mols SO2 / 3 mols O2 x 64 g SO2/mol SO2 = 134 g SO2