2H2O(g)↽−−⇀2H2(g)+O2(g) 2 ⁢ H 2 O ( g ) ⁢ ↽ − − ⇀ ⁢ 2 ⁢ H 2 ⁡ ( g ) + O 2 ⁡ ( g ) reach 0.0250 atm, 0.00550 atm, and 0.00400 atm

Question

The elementary reaction 

2H2O(g)↽−−⇀2H2(g)+O2(g)

proceeds at a certain temperature until the partial pressures of H2O, H2, and O2 reach 0.0250 atm, 0.00550 atm, and 0.00400 atm, respectively. What is the value of the equilibrium constant at this temperature?

Answer 1

2H₂O(g) <==> 2H₂(g) + O₂(g)

0.025.............0.0055......0.004......Equilibrium

Kp = (H₂)²(O₂) / (H₂O)²

Kp = (0.0055)²(0.004) / (0.025)²

Kp = 1.94x10^-4