J.R. S. answered 12/02/22
Ph.D. University Professor with 10+ years Tutoring Experience
1/2 X2(g) ==> X(g) .. ∆Gºf = 5.46 kJ/mol @ 2000K
1/2 X2(g) ==> X(g) .. ∆Gºf = -47.29 kJ/mol @ 3000K
NOTE: at 3000K, ∆Gº is negative meaning the reaction is spontaneous. At 2000, it is not spontaneous.
∆Gº = -RT ln K
@2000K:
5.46 kJ/mol = - (0.008314 kJ/molK)(2000K) ln K
K = 0.720
@3000K:
-47.29 kJ/mol = -(0.008314 kJ/molK)(3000K) ln K
K = 6.66
NOTE: At 3000K, K is >1 and at 2000K, K is <1 which is in agreement with spontaneity predicted above.