Consider a general reaction A(aq)⥫enzyme⥬B(aq)

Question

The Δ𝐺°′ of the reaction is −9.660 kJ·mol−1. Calculate the equilibrium constant for the reaction at 25 °C.

What is Δ𝐺 for the reaction at body temperature (37.0 °C) if the concentration of A is 1.6 M and the concentration of B is 0.50 M?

Answer 1

∆Gº = -RT ln K

∆Gº = -9.660 kJ/mol

R = 8.314 J/Kmol = 0.008314 kJ/Kmol

T = 25 + 273 = 298K

K = ?

Solving for K

-9.660 kJ/mol = -(0.008314 kJ/Kmol)(298K) ln K

-9.660 = -2.478 ln K

ln K = 3.898

K = 49.3

For the second question, what are A and B? What is the reaction, if any?