Elena H.

asked • 12/01/22

Find the equation of the circle shown in the figure.

The graph shows a circle with its center at (-2,2) and its diameter amost being from -5 to 1. The edges of the circle don't quite touch these though so i'm having trouble finding r.


I have: (x+2)^2+(y-2)^2=?

Lillian V.

Could the picture just be drawn poorly? I would think that the endpoints of the diameter would be "nice" numbers like -5 and 1, since the center is a "nice" number.
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12/01/22

Elena H.

No, i tried putting it in as if it had ended right on -5, and 1. I ended up guessing r^2=8 because root8 is almost 3 but not quite and it said I was right. I'm not sure how you would get there without guessing though.
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12/01/22

Lillian V.

Yeah, that is weird that they'd expect you to get r = sqrt(8) just by guessing! I'm glad you figured it out!
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12/01/22

Lillian V.

Unless: does the circle pass through the origin?
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12/01/22

Elena H.

Oh yes it does pass through the origin.
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12/01/22

Lillian V.

So do you see how to use that to find the value of r?
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12/01/22

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