How many calories of heat must be added to raise the temperature of 40 g of water from 25 to 300C?

Answer 1

q = mC∆T

q = heat = ?

m = mass = 40 g

C = specific heat of water = 1 cal / gº

∆T = change in temperature = 300º - 25º = 275º

Solving for q:

q = (40 g)(1 cal/gº)(275º)

q = 11,000 cal