find the smallest positive solution

Question

The smallest positive solution of the 3sin⁡(2x−1)−1=0

=

Answer 1

have

2x-1=sin^-1(1/3)+2k*pi

also

2x-1=pi-sin^-1(1/3)+2k*pi

solving first equation, k=0, x=.67 radians approx.

second equation, k=0, x=1.9 radians approx.

note plugging in either x to sin(2x-1) results in .334

Answer 2

sin (2x -1) = 1 / 3

Can you solve for x and answer?