use the system of equations to find the dimensions of the rectangle meeting in the specified conditions. The perimeter is 74 meter and the length is 3 meters greater than the width.

Answer 1

L = Length W = Width

Perimeter = 2 Length + 2 width 2L + 2W = 74

Length = Width + 3 L = W + 3

Substitute: 2 (W + 3) + 2W = 74

Distribute: 2W + 6 + 2W = 74

Combine: 4W + 6 = 74

Subtract: 4W = 68

Divide: W = 17

Length = 17 + 3 = 20