J.R. S. answered 11/29/22
Ph.D. University Professor with 10+ years Tutoring Experience
5.0 kg H2O / day x 12 days = 60.0 kg H2O needed to be heated
q = mC∆T
q = heat = ?
m = mass = 60.0 kg
C = specific heat of water = 4.184 kJ/kgº
∆T = change in temperature = 100º - 25º = 75º (100º is the boiling point of H2O)
q = (60.0 kg)(4.184 kJ/kgº)(75º) = 18,828 kJ of heat energy needed
Combustion of propane:
1 mol C3H8 = 103.8 kJ
molar mass C3H8 = 44 g/mol
25 g C3H8 x 1 mol / 44 g = 0.568 moles C3H8 / canister
0.568 mol C3H8 / canister x 103.8 kJ / mol = 59. kJ / canister
18,828 kJ x 1 canister / 59 kJ = 319+ canisters needed
Minimum number of canisters needed = 320 canisters