Raymond B. answered 02/17/24
Math, microeconomics or criminal justice
(96.3-97.1)//1.8= -.8/1.8= -8/18=-4/9=-.4444 = z
Area = .6716 = 67.16% probability M>96.3 cm
Javier R.
asked 11/28/22A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 97.1-cm and a standard deviation of 1.8-cm. For shipment, 25 steel rods are bundled together.
Find the probability that the average length of a randomly selected bundle of steel rods is greater than 96.3- cm
P(M>96.3-cm)
accurate to 4 decimal places
Raymond B. answered 02/17/24
Math, microeconomics or criminal justice
(96.3-97.1)//1.8= -.8/1.8= -8/18=-4/9=-.4444 = z
Area = .6716 = 67.16% probability M>96.3 cm
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