MnO4- (aq) + S2O42- (aq) → S4O62- (aq) + Mn2+(aq) Balance that acidic solution

Question

MnO₄^- (aq) + S₂O₄^2- (aq) → S₄O₆^2- (aq) + Mn²⁺(aq)

Balance that acidic solution

Answer 1

MnO₄^- (aq) + S₂O₄^2- (aq) → S₄O₆^2- (aq) + Mn²⁺(aq)

Are you sure the reactant is S₂O₄^2- and not S₂O₃^2-? The reason I ask is because is if S₂O₄^2- is the reactant and it goes to S₄O₆^2- as a product, this would be a reduction reaction. Why? Because S is going from +3 in S₂O₄^2- to +2.5 in S₄O₆^2-. This would not be possible since MnO₄^- => Mn²⁺ is also a reduction reaction (Mn going from +7 to +2). We would not have an oxidation half reaction, and that isn't possible. If the reactant were to be S₂O₃^2-, then we would have an oxidation half reaction. Please check to be sure you wrote the reaction correctly. Thanks.