Using this table of ionization constants, calculate the overall equilibrium constant, 𝐾overallKoverall, for the reaction.

Question

Using this table of ionization constants, calculate the overall equilibrium constant, 𝐾overallKoverall, for the reaction.

HF(aq)+S2−(aq)↽−−⇀F−(aq)+HS−(aq)

Answer 1

HF(aq) <==> H⁺(aq) + F^-(aq) ... K = 6.3x10^-4

H⁺(aq) + S^2-(aq) <==> HS^-(aq) ... K = 1/1x10^-19 = 1x10¹⁹

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HF(aq) + S^2-(aq) <==< HS^-(aq) + F^-(aq) ... K_overall = (6.3x10^-4)(1x10¹⁹) = 6.3x10¹⁵