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Question

Determine the current (in A) to produce 4.00 g Ag when Ag⁺(aq) is electrolyzed for 2.00 h. (F = 96,500 C/mol)

Answer 1

Ag⁺(aq) + e- ==> Ag(s)

4.00 g Ag x 1 mol Ag / 108 g = 0.0370 mols Ag

0.0370 mols Ag x 1 mol e- / mol Ag = 0.0370 mols e-

0.0370 mols e- x 96,5000 C / mol e- = 3574 C

2.00 hrs x 60 min / hr x 60 sec / min = 7200 seconds

A (amps) = C/s (coulombs / sec)

3574 C / 7200 s = 0.496 C/s = 0.496 A