What volume of concentrated acetic acid ( 17.4 M C H 3 O O H ) will be needed to prepare 5.00 L of 0.100 M acetic acid?

Answer 1

V1M1 = V2M2

V1 = initial volume = ?

M1 = initial molarity = (17.4 M)

V2 = final volume = 5.00 L

M2 = final molarity = 0.100 M

(x L)(17.4 M) = (5.00 L)(0.100 M0

x = 0.0287 L = 28.7 mls