Chemistry Question

Question

Small quantities of chlorine can be prepared in the laboratory by the reaction described by the equation

               MnO₂(s) + 4 HCl(aq) --> MnCl₂(aq) + Cl₂(g) + 2 H₂O(l)

How many grams of chlorine can be prepared from 6 grams of manganese(IV) oxide?

Answer 1

MnO₂(s) + 4 HCl(aq) --> MnCl₂(aq) + Cl₂(g) + 2 H₂O(l) ... balanced equation

Molar mass MnO₂ = 86.9 g / mol

Molar mass Cl₂ = 70.9 g / mol

Using dimensional analysis:

6 g MnO₂ x 1 mol MnO₂ / 86.9 g x 1 mol Cl₂ / 1 mol MnO₂ x 70.9 g Cl₂/mol = 5 g Cl₂ (1 sig. fig.)