J.R. S. answered 11/16/22
Ph.D. University Professor with 10+ years Tutoring Experience
q = mC∆T
q = heat = 4789 J
m = mass of water = 150.0 g
C = specific heat of water = 4.184 J/gº
∆T = change in temperature = 7.630º
Solving for q:
q = (150.0 g)(4.184 J/gº)(7.630º)
q = 4789 J heat from 0.001561 moles of C5H8
∆Hcombustion = 4789 J / 0.001561 moles = 3,067,905 J/mol = 3068 kJ/mol (4 sig. figs.)