through: (-5,-2), parallel to y=1/5x+2

Question

Write the slope-intercept for of the equation of the line described

Answer 1

You have asked several similar questions.

You really need to work on these yourself and ask specific questions if you have them.

For this one I assume you mean (1/5)x so that the equation you need is

1/5=(y+2)/(x+5)

You need to re-arrange this into slope-intercept form.

There are several ways to approach this problem. I usually use the point-slope form and re-arrange.

First of the correction you need to see is that written this way 1/5x means one divided by 5x, NOT 1/5 times x. If you do not make this correct, you will not be dealing with a straight line.

The point-slope form, in general, is m=(y-y₁)/(x-x₁). If you make a figure using the rise and run, you will see why this form is correct. To re-arrange into slope-intercept form, multiply both sides by (x-x₁), then expand on the left and collect terms. I hope this helps.

Please note that slope=0 means the line is parallel to the x-axis and the equation will be y=y₁, where y₁ is given in the point. The equation x=5 is parallel to the y-axis and you can think of this as a line with infinite slope.