J.R. S. answered 11/15/22
Ph.D. University Professor with 10+ years Tutoring Experience
Ag+(aq) + 1e- ==> Ag(s)
3.50 amps = 3.50 C/s
1.80 h x 60 min / h x 60 s / min = 6480 seconds (s)
3.50 C / s x 6480 s = 22,680 C
It takes 96,500 C for each 1 mole of electrons, so ...
22.680 C x 1 mol e- / 96,500 C = 0.235 mols electrons
0.235 mols e- x 1 mol Ag / 1 mol e- = 0.235 mols Ag
Mass of Ag = 0.235 mols Ag x 107.9 g Ag / mol = 25.4 g Ag produced
(be sure to check the math)