Calculate the volume in milliliters of a 1.3/molL iron(II) bromide solution that contains 50.0g of iron(II) bromide FeBr2

Question

Calculate the volume in milliliters of a 1.3/molL

 iron(II) bromide solution that contains 50.0g

 of iron(II) bromide FeBr2

. Be sure your answer has the correct number of significant digits.

Answer 1

Molar mass FeBr₂ = 215.7 g / mol

Moles of FeBr₂ in 50.0 g: 50.0 g x 1 mol / 215.7 g = 0.2318 moles FeBr₂

Volume of 1.3 M FeBr₂ needed = 0.2318 mols x 1 L / 1.3 mols = 0.178 L = 178 mls (3. sig. figs.)