J.R. S. answered 11/13/22
Ph.D. University Professor with 10+ years Tutoring Experience
C2H3O2- ==> CO2
C2H3O2- ==> 2CO2 ... balanced for C
C2H3O2- + 2H2O ==> 2CO2 ... balanced for C and O
C2H3O2- + 2H2O ==> 2CO2 + 7H+ ... balanced for C, O and H (using acid, H+)
C2H3O2- + 2H2O ==> 2CO2 + 7H+ + 8e- ... balanced for C, O, H and charge = balanced equation
Since electrons are on the right side, this is an oxidation half reaction.
C2H3O2- ==> CO2
C2H3O2- ==> 2CO2 ... balanced for C
C2H3O2- + 2H2O ==> 2CO2 ... balanced for C and O
C2H3O2- + 2H2O + 7OH- ==> 2CO2 + 7H2O ... balanced for C, O and H (using base, OH-)
C2H3O2- + 2H2O + 7OH- ==> 2CO2 + 7H2O + 8e- ... balanced for C, O, H, and charge = balanced equation
Since electrons appear on the right side, this is an oxidation half reaction