how do you write an equation for a line parallel to the line y=-3x+1 that passes through point (2,8)?

Answer 1

y=-3x+b

8=-3(2)+b

b = 8+6 =14

y=-3x +14 is the equation of the parallel line through the point (2,8).

Parallel lines have the same slope = the coefficient of the x term when the linear equation is solved for y = -3