What is 2÷cos∅=7-3cos∅

Answer 1

2/cosT = 7-3cosT

2 = 7cosT -3cos^2(T)

3cos^2(T) -7cosT +2 = 0

(3cosT-1)(cosT-2) = 0

cosT =2 (ignore this answer as it's impossible, since cosines are always<2)

cosT =1/3, T is in quadrant I or IV

use a calculator with an inverse trig function

T = about +/- 70.53

Theta = about 70.53 +360n degrees where n = any integer

or about -70.53 + 360n degrees, where n = any integer

check the answer

2/(1/3) = 7 -3(1/3)

2(3) =7-1

6=6

cos70.53 = about 0.333313 = about 1/3

70.53 degrees = about 1.231 radians = about 0.4pi radians

T=about .4pi +2npi or about -.4pi+2npi where n = any integer