The equilibrium constant for the chemical equation N2(g)+3H2(g)↽−−⇀2NH3(g) is K p = 0.0343 at 257 °C. Calculate the value of the 𝐾c K c for the reaction at 257 °C .

Answer 1

N₂(g) + 3H₂(g) <==> 2NH3(g)

Kc = Kp(RT)^-∆n

Kc = ?

Kp = 0.0343

R = gas constant = 0.0821 Latm/Kmol

T = temp in K = 257ºC + 273 = 530K

∆n = change in moles of gas = 2 - 4 = -2

Kc = (0.0343)(0.0821 * 530)²

Kc = (0.0343)(1893)

Kc = 64.9