J.R. S. answered 11/11/22
Ph.D. University Professor with 10+ years Tutoring Experience
∆E = RH (1/nf2 - 1/ni2)
∆E = change in energy = ?
RH = -2.179x10-18 J
nf = final energy level = 1
ni = initial energy level = 3
∆E = -2.179x10-18 J (1/1 - 1/9) = -2.179x10-18 J (0.8889)
∆E = -1.05x10-18 J (negative since energy is released when falling from higher to lower energy level)
To find the wavelength, use E = hc / λ
E = energy = 1.05x10-18 J
h = Planck's constant = 6.626x10-34 Js
c = speed of light = 3x108 m/s
λ = wavelength = ?
Solving for λ, we have ...
λ = hc / E = (6.626x10-34 Js)(3x108 m/s) / 1.05x10-18 J
λ = 1.89x10-7 m = 189 nm
Cannon D.
Thank you11/11/22