Chemistry problem!

Question

How much is needed pure oxygen when 300 kg of methanol burns perfectly?

Answer 1

Methanol = CH3OH

2CH₃OH + 3O₂ ==> 2CO₂ + 4H₂O ... balanced equation for complete combustion of methanol

molar mass CH3OH = 32 g / mol

300 kg CH3OH x 1000 g / kg x 1 mol / 32 g = 9375 moles CH3OH

mass O2 needed = 9375 mols CH3OH x 3 mol O2 / 2 mol CH3OH x 32 g O2 / mol = 450,000 g O2

Or ... 450 kg of O2