J.R. S. answered 04/03/25
Ph.D. University Professor with 10+ years Tutoring Experience
Let's use the formula ∆T = imK
∆T = change in the freezing point = 11ºC (normal freezing point is 0º, so -11º is a change of 11º)
i = van't Hoff factor = 1 since sucralose does not ionize
m = molality of sucralose (see below)
K = freezing constant for water = 1.86º/m
Now we will solve the equation for m (molality of sucralose)
11 = (1)(m)(1.86)
m = 5.91 moles/kg water
Since we have 1 kg of water, the maximum moles of sucralose would be 5.91 moles.
The question asks for mass of sucralose, so we can now easily calculate that.
Molar mass sucralose = 12x12 + 19x1 + 3x35.5 + 16x8 = 398 (rounded to 3 sig.figs.)
mass of sucralose =5.91 moles x 398 g / mole = 2352 g = 2350 g Sucralose (3 sig.figs.)