J.R. S. answered 11/09/22
Ph.D. University Professor with 10+ years Tutoring Experience
2S2O32- + I3- ==> S4O62- + 3I-
moles S2O32- = 42.2 ml x 1 L / 1000 ml x 0.310 mol / L = 0.01308 mols
moles I3- = 0.01308 mols S2O32- x 1 mol I3- / 2 mol S2O32- = 0.006541 mols
Molarity of I3- solution = 0.006541 mols / 30.0 ml x 1000 ml / L = 0.218 moles / L = 0.218 M