J.R. S. answered 04/05/25
Ph.D. University Professor with 10+ years Tutoring Experience
Here is the correctly balanced equation for the complete combustion of methanol (CH3OH)
2CH3OH + 3O2 ==> 2CO2 + 4H2O ... balanced equation
The molar mass of methanol = 32.0 g/mole
Moles in 404 kg = 404 kg x 1000 g / kg x 1 mol / 32.0 g = 12625 moles of methanol
Using the stoichiometry of the balanced equation, we will calculate the moles of CO2 produced...
12625 mol CH3OH x 2 mols CO2 / 2 mols CH3OH = 12625 moles of CO2 produced
This question didn't ask for mass, but to calculate mass CO2 produced, we use the molar mass of CO2..
molar mass CO2 = 44.0 g / mol
12625 mols CO2 x 44.0 g / mol = 555500 g = 555.5 kg = 556 kg of CO2 produced (3 sig.figs.)