J.R. S. answered 11/07/22
Ph.D. University Professor with 10+ years Tutoring Experience
We first need to find out how much heat is generated burning the cashew.
q = mCcal∆T
q = heat = ?
m = mass of water = 0.245 kg
Ccal = calorimeter constant = 850 kcal / kgº
∆T = change in temperature = 3.65º
Solving for q we have...
q = (0.245 kg)(850 kcal / kgº)(3.65º)
q = 760.1 kcal
760.1 kcal x 1 g fat / 9.00 kcal = 84.5 g of fat (rounded to 3 sig. figs.)