A titration is preformed to find the concentration of the H2SO4. 48.67mL of an unknown sulfuric acid and 80.33mL of 0.36M KOH. What is the concentration of the sulfuric acid solution?

Answer 1

Ok Sarah, let's first write the correctly balanced equation. This is a must!

H2SO4 + 2KOH ==> K2SO4 + 2H2O ... balanced equation

Now we find the moles of KOH needed to completely react with the H2SO4

moles KOH = 80.33 ml x 1 L / 1000 ml x 0.36 mols / L = 0.02892 moles

Next, we use the stoichiometry of the balanced equation to find moles H2SO4 present

0.02892 mols KOH x 1 mol H2SO4 / 2 mols KOH = 0.01446 mols H2SO4

Finally, we divide the moles by the liters of H2SO4 to obtain mol/L = molarity (concentration)

0.01446 mols / 48.67 ml x 1000 ml / L = 0.297 moles / L = 0.30 M (2 sig. figs.) = Answer