
Tom B. answered 11/04/22
Experienced, Friendly, and Plain-Speaking Math Tutor
One of the trig identities you typically learn is that cos(π/2-x) = sin(x). So in your problem cos(π/2-x) = .49
But if you don't remember that one, you can use the cos(u-v) = cos u cos v + sin u sin v.
So cos(π/2-x) = cos π/2 cos x + sin π/2 sin x. Conveniently, cos π/2 = 0. So, cos(π/2-x) = 0 cos x + 1 sin x = sin x.