Find the radius of the circle 2x^2+2y^2-8x+12y-28=0

Answer 1

2x^2-8x +2y^2+12y =28

divide by 2 and complete squares

x^2-4x +4 +y^2 +6y +9 =14+9+4= 27

radius =sqr27= 3sqr3= about 3(1.732)

radius = 3sqr3 = about 5.196

center = (2,-3)