J.R. S. answered 11/03/22
Ph.D. University Professor with 10+ years Tutoring Experience
There are various ways to approach these problems, but for first order decay, one easy way is to use the following relationship:
FR = 0.5n
where FR = fraction remaining
n = number of half lives that have elapsed
(1). half life = 72.9 hours; fraction remaining (FR) = 23.1% = 0.231
FR = 05n and we will solve for n (number of half lives that have elapsed)
0.231 = 0.5n
log 0.231 = n log 0.5
-0.636 = -0.301 n
n = 2.11 half lives have elapsed, and since each half life is 72.9 hours, we can find the time it took...
2.11 half lives x 72.9 hours / half life = 154 hours
(2). Fraction remaining (FR) = 14.6% = 0.146
FR = 0.5n
0.146 = 0.5n
log 0.146 = n log 0.5
-0.836 = -0.301 n
n = 2.78 half lives have elapsed and this is equal to the 2.14 seconds that it took, so we can find the 1/2 life..
2.14 sec / 2.78 half lives = 0.770 seconds / half life
So the half life of boron-8 would be ~ 0.770 seconds
See if you can do #3. Hint: FR = 3.77x10-2 / 0.255. Answer should be in the neighborhood of 15,800 years