J.R. S. answered 11/03/22
Ph.D. University Professor with 10+ years Tutoring Experience
Set up an ICE table:
2HI(g) <===> H2(g) + I2(g)
0.247...............0.............0..........Initial
-2x..................+x...........+x.........Change
0.247-2x..........x.............x..........Equilibrium
K = [H2][I2] / [HI]2
2.68x10-2 = (x)(x) / (0.247-2x)2
Use the quadratic formula to solve for x
When you find the value of x, go back to the equilibrium line of the ICE table and plug in x and solve for the concentrations of each gas.