Determine the equilibrium constant?

Question

Determine the equilibrium constant for a reaction at 200.0 K if ∆G° =-13.00 kJ/mol. (R = 8.314 J/mol ･ K)

Answer 1

∆Gº = -RT ln K

-13.00 kJ/mol = -(0.008314 kJ/molK)(200K) ln K ... (note changed units of R to match those for ∆Gº)

ln K = -13.00 kJ/mol / -(0.008314 kJ/molK)(200K)

ln K = 7.818

K = 2485