J.R. S. answered 11/02/22
Ph.D. University Professor with 10+ years Tutoring Experience
Kar,
You have asked many, many, many questions dealing with Ksp and solubility. I have answered many, many of them. I will answer this one as well, but I sure hope you are getting the hang of it, and that you can do them by yourself in the future.
Cr(OH)3(s) <==> Cr3+(aq) + 3OH-
Ksp = [Cr3+][OH-]3
From the pH value of 10.00, we can find the OH- concentration. Plug that into the Ksp expression and solve for [Cr3+]
pH = 10.00 so pOH = 14 - 10 = 4.00
[OH-] = 1x10-4 M
6.7x10-31 = [Cr3+][1x10-4]3 = [Cr3+][1.00x10-12]
[Cr3+] = 6.70x10-19 M = solubility of Cr(OH)3 at pH 10