J.R. S. answered 11/02/22
Ph.D. University Professor with 10+ years Tutoring Experience
O2 + 4Li ==> 2Li2O
O2 + 4e- ==> 2 O2- ... oxidation half reaction
4Li ==> 4Li+ + 4e- ... reduction half reaction
Ju O.
asked 11/02/22Separate the redox reaction into its component half‑reactions.
O2+4Li⟶2Li2O
Use the symbol e− for an electron.
oxidation half-reaction:
reduction half-reaction:O2+4e-->2O-2
J.R. S. answered 11/02/22
Ph.D. University Professor with 10+ years Tutoring Experience
O2 + 4Li ==> 2Li2O
O2 + 4e- ==> 2 O2- ... oxidation half reaction
4Li ==> 4Li+ + 4e- ... reduction half reaction
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.