J.R. S. answered 11/02/22
Ph.D. University Professor with 10+ years Tutoring Experience
∆U = q + w
∆U = Internal energy = ?
q = heat = -174.0 J (negative b/c the system LOSES heat)
w = work = -P∆V (pressure-volume work) = -(3.77 atm)(1.00 - 13.51 L)
w = -3.77 atm * -12.51 L
w = 47.16 Latm
Converting this to joules, we have 47.16 Latm x 101.325 J / 1 Latm = 4778 J (positive b/c work is being
done ON the system (compression).
∆U = q + w = -174.0 J + 4778 J
∆U = 4604 J = 4.60 kJ