An aqueous containing

Question

An aqueous solution containing 8.31 g of lead(II) nitrate is added to an aqueous solution containing 6.41 g  of potassium chloride.

Enter the balanced chemical equation for this reaction. Be sure to include all physical states.

a.) What is the limiting reactant

b.) The percent yield for the reaction is 87.3%. How many grams of the precipitate are formed?

c.) Taking into account the percent yield, how many grams of the excess reactant (the reactant that is not limiting) remain?

Answer 1

Pb(NO3)2(aq) + 2KCl(aq) ==> PbCl2(s) + 2NaNO3(aq) ... balanced equation

Find limiting reactant as described in my previous answer to your similar question.

Use the moles of limiting reactant to find moles and grams of PbCl2 (the precipitate)

Take 87.3% of that that answer to give you the actual grams of precipitate formed.

Find remaining KCl as described in my answer to your previous question.