J.R. S. answered 10/31/22
Ph.D. University Professor with 10+ years Tutoring Experience
Zn(OH)2(s) <==> Zn2+(aq) + 2OH-(aq)
Ksp = [Zn2+][OH-]2
3.0x10-16 = (x)(2x)2
4x3 = 3.0x10-16
x3 = 7.5x10-17
x = 4.22x10-6 = [Zn2+]
[OH-] = 2 x 4.22x10-6 = 8.44x10-6 M
pOH = -log 8.44x10-6 M
pOH = 5.07
pH = 14 - 5.07
pH = 8.93