Marla G. answered 11/10/22
Masters Degree in Applied Statistics with 20+ Years of Work Experience
Since we can assume the data is from a normal distribution,and our n=16, which < 30, we need 2 use the values from a t-distribution in our formula to calculate any confidence interval. Here is that formula: Confidence Interval = x̄ ± tα/2(S/√n). For a 98% interval you need to find the T value for alpha/2= 0.02/2=0.01.
You have all the number to plug in the formula, so I'll let you finish this problem.