Ruth B.
asked 10/30/22Statistics question
Adult male height is normally distributed with a mean of 69 inches and a standard deviation of 2.29 inches. If an adult male is randomly selected, what is the probability that the adult male has a height between 64.6 and 69.1 inches? Round your final answer to four decimal places.
1 Expert Answer
On this type of question you want to first use the formula
z = (x – mean) / (standard deviation) in order to convert the given values over into a Z score. then once you have done that you can use technology like a calculator or Microsoft Excel to convert the value over into a probability.
From the values in the question we get
z = (64.6 – 69)/2.29 = -1.9214
z = (69.1 – 69)/2.29 = 0.0437
for the Z values
using technology to convert that over then I get 0.4900 for the resulting probability
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Sukumar R.
Statistics question Adult male height is normally distributed with a mean of 69 inches and a standard deviation of 2.29 inches. If an adult male is randomly selected, what is the probability that the adult male has a height between 64.6 and 69.1 inches? Round your final answer to four decimal places. Step-1 Given: mu = 69 Sigma= 2.29 Step-2 Compute z-score of 64.6 z(64.6) =(64.6-69)/2.29 = -1.9214 Compute probability of 64.6 from z-table where z=-1.9214 0r z=-1.92 >> -0.0281 Compute z-score of 69.1 z(69.1) = =(69.1-69)/2.29 = 0.044 Compute probability of 69 from z-table where z=0.044 >> 0.6700 Step-3 Compute required probability -0.0281 <p <0.67 >> 0.6981 Answer: Probability that adult male has a height between 64.6 and 69.1 inches = 0.698111/07/22