J.R. S. answered • 10/30/22
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(1). Ca (atomic no. 20). Period 4, group 2. S block.
1s2 2s2 2p6 3s2 3p6 4s2
(2). Cl (atomic no. 17). Period 3, group 17. P block.
1s2 2s2 2p6 3s2 3p5
(3). Te (atomic no. 52). Period 5, group 16. P block
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p4
(4). Kr (atomic no. 36). Period 4, group 18. P block
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6
J.R. S.
tutor
First of all, there is no element te, nor is there an element KR. Maybe you mean Te and Kr. And instead of saying "wrong", why not provide the correct answer. Actually the configurations provided ARE correct. Maybe you need to put 3d10 before 4s2 for Kr and maybe put 3d10 before 4s2 and put 5p4 for Te, but that's just convention. The configurations I presented are correct to the best of my knowledge. Study chemistry a little more before you so blatantly tell someone there answer is wrong.
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10/30/22
Baran M.
te and KR are wrong10/30/22