What is the image point of (-9,0)(−9,0) after the transformation r_{\text{y-axis}}\circ T_{2,3}r y-axis ​ ∘T 2,3 ​ ?

Answer 1

Hi Maya,

If this is the composite transformations that you have to perform R_yaxisoT<2,3>

Step 1 would be to perform T_<2,3> for the given point (-9,0). T stands for translation- in this case 2 units to the right of -9 and 3 units above 0. The point would end up at ( -7,3).

Step 2 you reflect (-7,3) over the y-axis. The point would end up at ( 7,3) and that is the answer.

To reflect over y-axis the rule is (a,b)-->(-a, b). You can also see it better on a coordinate plane.

Hope that is your question.