Calculate how many C2H4 molecules are contained in 45.8 mg of C2H4.

Answer 1

There are 6.022x10²³ molecules (Avogadro's number) in 1 mole.

molar mass C2H4 = 28 g / mole

45.8 mg C2H4 x 1 g / 1000 mg x 1 mol / 28 g = 0.001636 moles C2H4

0.001636 mols x 6.022x10²³ molecules / mole = 9.85x10²⁰ molecules of C2H4