A 8.30 L8.30 L container holds a mixture of two gases at 37 °C.37 °C. The partial pressures of gas A and gas B, respectively, are 0.294 atm0.294 atm and 0.843 atm.0.843 atm.

Question

If 0.230 mol0.230 mol of a third gas is added with no change in volume or temperature, what will the total pressure become?

Answer 1

To find the total pressure, we need to find the partial pressure of the third gas, and then just add that to the pressures of gas A and gas B to get total pressure.

Refer to Dalton's Law of partial pressure

Ideal gas law: PV = nRT where P=pressure; V=volume; n=moles; R=gas constant; T=temperature

Solving for the pressure (P) of the third gas: P = nRT/V

P = (0.230 mol)(0.0821 Latm/Kmol)(310K) / 8.30 L

P = 0.705 atm

Total Pressure = 0.294 atm + 0.843 atm + 0.705 atm

Total Pressure = 1.842 atm