J.R. S. answered 10/27/22
Ph.D. University Professor with 10+ years Tutoring Experience
KE(avg) = 3/2 nRT
KE(avg) = 3/2 (1 mol)(8.314 J/Kmol)(619K)
KE(avg) = 7720 J
KE(avg) = 3/2 KBT where KB is Boltzman constant = 1.38x10-23 J / K * molecule
KE(avg) = 3/2 (1.38x10-23 J / K * molecule)(619K)
KE(avg) = 1.28x10-20 J / molecule
or...
7720 J / mol * 1 mol / 6.022x1023 molecules = 1.28x10-20 J / molecule