If n=17, ¯ x x ¯ (x-bar)=32, and s=3, find the margin of error at a 98% confidence level

Answer 1

margin of error is t-critical * s / sqrt(n)

critical probability = 0.99

t-critical for 0.99 probability and 17 - 1= 16 degrees of freedom is 2.583

margin of error = 2.583 * 3/sqrt(17)