J.R. S. answered 04/06/25
Ph.D. University Professor with 10+ years Tutoring Experience
The solution described in this problem is a buffer since it contains a weak acid (HNO2) and the conjugate base (NaNO2). To determine the pH, we can use the Henderson Hasselbalch equation...
pH = pKa + log [conj.base]/[acid]
pH = ?
pKa = -log Ka = -log 4.5x10-4 = 3.35
[conj.base] = 0.220 M
[acid] = 0.300
Solving for pH...
pH = 3.35 + log (0.220/0.300) = 3.35 + 1.824
pH = 5.17